From: Colin Ian King <colin.i.king@gmail.com>
Date: Wed, 7 May 2025 10:43:37 +0000 (+0100)
Subject: kdb: remove redundant check for scancode 0xe0
X-Git-Url: https://www.infradead.org/git/?a=commitdiff_plain;h=fdbdd0ccb30af18d3b29e714ac8d5ab6163279e0;p=users%2Fhch%2Fmisc.git

kdb: remove redundant check for scancode 0xe0

The check for scancode 0xe0 is always false because earlier on
the scan code is masked with 0x7f so there are never going to
be values greater than 0x7f. Remove the redundant check.

Signed-off-by: Colin Ian King <colin.i.king@gmail.com>
Reviewed-by: Douglas Anderson <dianders@chromium.org>
Signed-off-by: Daniel Thompson (RISCstar) <danielt@kernel.org>
---

diff --git a/kernel/debug/kdb/kdb_keyboard.c b/kernel/debug/kdb/kdb_keyboard.c
index 3a74604fdb8a..386d30e530b7 100644
--- a/kernel/debug/kdb/kdb_keyboard.c
+++ b/kernel/debug/kdb/kdb_keyboard.c
@@ -145,9 +145,6 @@ int kdb_get_kbd_char(void)
 		return CTRL('F');
 	}
 
-	if (scancode == 0xe0)
-		return -1;
-
 	/*
 	 * For Japanese 86/106 keyboards
 	 * 	See comment in drivers/char/pc_keyb.c.