Pinmux registers ends at 0x000f42ac (including). Thus, the size argument
of the pinctrl-single node has to be 0x2b0. Fix it.
This will fix the following error:
pinctrl-single f4000.pinctrl: mux offset out of range: 0x2ac (0x2ac)
Fixes: 29075cc09f43 ("arm64: dts: ti: Introduce AM62P5 family of SoCs")
Signed-off-by: Michael Walle <mwalle@kernel.org>
Link: https://lore.kernel.org/r/20250618065239.1904953-1-mwalle@kernel.org
Signed-off-by: Vignesh Raghavendra <vigneshr@ti.com>
main_pmx0: pinctrl@f4000 {
compatible = "pinctrl-single";
- reg = <0x00 0xf4000 0x00 0x2ac>;
+ reg = <0x00 0xf4000 0x00 0x2b0>;
#pinctrl-cells = <1>;
pinctrl-single,register-width = <32>;
pinctrl-single,function-mask = <0xffffffff>;