Each pair of DPs only needs to be compared once when searching for
a non-unique prio value.
Signed-off-by: David Ward <david.ward@ll.mit.edu>
Acked-by: Jamal Hadi Salim <jhs@mojatatu.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
                if (q == NULL)
                        continue;
 
-               for (n = 0; n < table->DPs; n++)
-                       if (table->tab[n] && table->tab[n] != q &&
-                           table->tab[n]->prio == q->prio)
+               for (n = i + 1; n < table->DPs; n++)
+                       if (table->tab[n] && table->tab[n]->prio == q->prio)
                                return 1;
        }