One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array.  For example:
  struct foo {
      int stuff;
      void *entry[];
  };
  instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
  instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);
This code was detected with the help of Coccinelle.
Link: http://lkml.kernel.org/r/20190109172445.GA15908@embeddedor
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Reviewed-by: Peter Oberparleiter <oberpar@linux.ibm.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
 
        /* Duplicate gcov_info. */
        active = num_counter_active(info);
-       dup = kzalloc(sizeof(struct gcov_info) +
-                     sizeof(struct gcov_ctr_info) * active, GFP_KERNEL);
+       dup = kzalloc(struct_size(dup, counts, active), GFP_KERNEL);
        if (!dup)
                return NULL;
        dup->version            = info->version;
 {
        struct gcov_iterator *iter;
 
-       iter = kzalloc(sizeof(struct gcov_iterator) +
-                      num_counter_active(info) * sizeof(struct type_info),
+       iter = kzalloc(struct_size(iter, type_info, num_counter_active(info)),
                       GFP_KERNEL);
        if (iter)
                iter->info = info;