btrfs: check-integrity: simplify bio allocation in btrfsic_read_block

btrfsic_read_block does not need the btrfs_bio structure, so switch to
plain bio_alloc (that also does not fail as it's backed by a bioset).

Reviewed-by: Qu Wenruo <wqu@suse.com>
Signed-off-by: Christoph Hellwig <hch@lst.de>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>

diff --git a/fs/btrfs/check-integrity.c b/fs/btrfs/check-integrity.c
index ab27b2c1045600f80c2d3168a8ddcf8883ddc1d8..5d20137b7b676bcf546c7da8f360f445a412b41e 100644 (file)
--- a/fs/btrfs/check-integrity.c
+++ b/fs/btrfs/check-integrity.c
@@ -1561,10 +1561,9 @@ static int btrfsic_read_block(struct btrfsic_state *state,
                struct bio *bio;
                unsigned int j;
 
-               bio = btrfs_bio_alloc(num_pages - i);
-               bio_set_dev(bio, block_ctx->dev->bdev);
+               bio = bio_alloc(block_ctx->dev->bdev, num_pages - i,
+                               REQ_OP_READ, GFP_NOFS);
                bio->bi_iter.bi_sector = dev_bytenr >> 9;
-               bio->bi_opf = REQ_OP_READ;
 
                for (j = i; j < num_pages; j++) {
                        ret = bio_add_page(bio, block_ctx->pagev[j],