The callers are ensuring that another interface doesn't exist with the
same interface id and so there is no need to check that from
gb_interface_create() anymore.
Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
Reviewed-by: Johan Hovold <johan@hovoldconsulting.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@google.com>
        struct gb_interface *intf;
        int retval;
 
-       intf = gb_interface_find(hd, interface_id);
-       if (intf) {
-               dev_err(hd->parent, "Duplicate interface with interface-id: %d will not be created\n",
-                       interface_id);
-               return NULL;
-       }
-
        module = gb_module_find(hd, endo_get_module_id(hd->endo, interface_id));
        if (!module)
                return NULL;