int err;
 
        s_idx = ctx->idx;
-       for (node = rb_first(root); node; node = rb_next(node)) {
+
+       /* If this is not the first invocation, ctx->idx will contain the id of
+        * the last nexthop we processed. Instead of starting from the very
+        * first element of the red/black tree again and linearly skipping the
+        * (potentially large) set of nodes with an id smaller than s_idx, walk
+        * the tree and find the left-most node whose id is >= s_idx.  This
+        * provides an efficient O(log n) starting point for the dump
+        * continuation.
+        */
+       if (s_idx != 0) {
+               struct rb_node *tmp = root->rb_node;
+
+               node = NULL;
+               while (tmp) {
+                       struct nexthop *nh;
+
+                       nh = rb_entry(tmp, struct nexthop, rb_node);
+                       if (nh->id < s_idx) {
+                               tmp = tmp->rb_right;
+                       } else {
+                               /* Track current candidate and keep looking on
+                                * the left side to find the left-most
+                                * (smallest id) that is still >= s_idx.
+                                */
+                               node = tmp;
+                               tmp = tmp->rb_left;
+                       }
+               }
+       } else {
+               node = rb_first(root);
+       }
+
+       for (; node; node = rb_next(node)) {
                struct nexthop *nh;
 
                nh = rb_entry(node, struct nexthop, rb_node);
-               if (nh->id < s_idx)
-                       continue;
 
                ctx->idx = nh->id;
                err = nh_cb(skb, cb, nh, data);