bt_sock_alloc() attaches allocated sk object to the provided sock object.
If rfcomm_dlc_alloc() fails, we release the sk object, but leave the
dangling pointer in the sock object, which may cause use-after-free.
Fix this by swapping calls to bt_sock_alloc() and rfcomm_dlc_alloc().
Signed-off-by: Ignat Korchagin <ignat@cloudflare.com>
Reviewed-by: Kuniyuki Iwashima <kuniyu@amazon.com>
Reviewed-by: Eric Dumazet <edumazet@google.com>
Link: https://patch.msgid.link/20241014153808.51894-4-ignat@cloudflare.com
Signed-off-by: Jakub Kicinski <kuba@kernel.org>
 
        struct rfcomm_dlc *d;
        struct sock *sk;
 
-       sk = bt_sock_alloc(net, sock, &rfcomm_proto, proto, prio, kern);
-       if (!sk)
+       d = rfcomm_dlc_alloc(prio);
+       if (!d)
                return NULL;
 
-       d = rfcomm_dlc_alloc(prio);
-       if (!d) {
-               sk_free(sk);
+       sk = bt_sock_alloc(net, sock, &rfcomm_proto, proto, prio, kern);
+       if (!sk) {
+               rfcomm_dlc_free(d);
                return NULL;
        }