bt_sock_alloc() attaches allocated sk object to the provided sock object.
If rfcomm_dlc_alloc() fails, we release the sk object, but leave the
dangling pointer in the sock object, which may cause use-after-free.
Fix this by swapping calls to bt_sock_alloc() and rfcomm_dlc_alloc().
Signed-off-by: Ignat Korchagin <ignat@cloudflare.com>
Reviewed-by: Kuniyuki Iwashima <kuniyu@amazon.com>
Reviewed-by: Eric Dumazet <edumazet@google.com>
Link: https://patch.msgid.link/20241014153808.51894-4-ignat@cloudflare.com
Signed-off-by: Jakub Kicinski <kuba@kernel.org>
struct rfcomm_dlc *d;
struct sock *sk;
- sk = bt_sock_alloc(net, sock, &rfcomm_proto, proto, prio, kern);
- if (!sk)
+ d = rfcomm_dlc_alloc(prio);
+ if (!d)
return NULL;
- d = rfcomm_dlc_alloc(prio);
- if (!d) {
- sk_free(sk);
+ sk = bt_sock_alloc(net, sock, &rfcomm_proto, proto, prio, kern);
+ if (!sk) {
+ rfcomm_dlc_free(d);
return NULL;
}