evsel__is_hybrid returns true if there are multiple core PMUs and the
evsel is for a core PMU. Determining the number of core PMUs can
require loading/scanning PMUs. There's no point doing the scanning if
evsel for the is_hybrid test isn't core so reorder the tests to reduce
PMU scanning.
Signed-off-by: Ian Rogers <irogers@google.com>
Reviewed-by: Kan Liang <kan.liang@linux.intel.com>
Link: https://lore.kernel.org/r/20250201074320.746259-2-irogers@google.com
Signed-off-by: Namhyung Kim <namhyung@kernel.org>
*/
bool evsel__is_hybrid(const struct evsel *evsel)
{
- if (perf_pmus__num_core_pmus() == 1)
+ if (!evsel->core.is_pmu_core)
return false;
- return evsel->core.is_pmu_core;
+ return perf_pmus__num_core_pmus() > 1;
}
struct evsel *evsel__leader(const struct evsel *evsel)