bpf, i386: Remove unneeded conversion to bool

The '==' expression itself is bool, no need to convert it to bool again.
This fixes the following coccicheck warning:

  arch/x86/net/bpf_jit_comp32.c:1478:50-55: WARNING: conversion to bool not needed here
  arch/x86/net/bpf_jit_comp32.c:1479:50-55: WARNING: conversion to bool not needed here

Signed-off-by: Jason Yan <yanaijie@huawei.com>
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Acked-by: Martin KaFai Lau <kafai@fb.com>
Link: https://lore.kernel.org/bpf/20200506140352.37154-1-yanaijie@huawei.com

diff --git a/arch/x86/net/bpf_jit_comp32.c b/arch/x86/net/bpf_jit_comp32.c
index 66cd150b7e541d77302819298284ec3b81c54b12..96fde03aa9877a68f978cbef19b35a222baef633 100644 (file)
--- a/arch/x86/net/bpf_jit_comp32.c
+++ b/arch/x86/net/bpf_jit_comp32.c
@@ -1475,8 +1475,8 @@ static int do_jit(struct bpf_prog *bpf_prog, int *addrs, u8 *image,
        for (i = 0; i < insn_cnt; i++, insn++) {
                const s32 imm32 = insn->imm;
                const bool is64 = BPF_CLASS(insn->code) == BPF_ALU64;
-               const bool dstk = insn->dst_reg == BPF_REG_AX ? false : true;
-               const bool sstk = insn->src_reg == BPF_REG_AX ? false : true;
+               const bool dstk = insn->dst_reg != BPF_REG_AX;
+               const bool sstk = insn->src_reg != BPF_REG_AX;
                const u8 code = insn->code;
                const u8 *dst = bpf2ia32[insn->dst_reg];
                const u8 *src = bpf2ia32[insn->src_reg];