io_sqe_buffer_register() currently calls io_put_rsrc_node() if it fails
to fully set up the io_rsrc_node. io_put_rsrc_node() is more involved
than necessary, since we already know the reference count will reach 0
and no io_mapped_ubuf has been attached to the node yet.
So just call io_free_node() to release the node's memory. This also
avoids the need to temporarily set the node's buf pointer to NULL.
Signed-off-by: Caleb Sander Mateos <csander@purestorage.com>
Link: https://lore.kernel.org/r/20250228235916.670437-3-csander@purestorage.com
Signed-off-by: Jens Axboe <axboe@kernel.dk>
node = io_rsrc_node_alloc(ctx, IORING_RSRC_BUFFER);
if (!node)
return ERR_PTR(-ENOMEM);
- node->buf = NULL;
ret = -ENOMEM;
pages = io_pin_pages((unsigned long) iov->iov_base, iov->iov_len,
if (imu)
io_free_imu(ctx, imu);
if (node)
- io_put_rsrc_node(ctx, node);
+ io_free_node(ctx, node);
node = ERR_PTR(ret);
}
kvfree(pages);